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2(x-3)+9=(x-1)+x
We move all terms to the left:
2(x-3)+9-((x-1)+x)=0
We multiply parentheses
2x-((x-1)+x)-6+9=0
We calculate terms in parentheses: -((x-1)+x), so:We add all the numbers together, and all the variables
(x-1)+x
We add all the numbers together, and all the variables
x+(x-1)
We get rid of parentheses
x+x-1
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
2x-(2x-1)+3=0
We get rid of parentheses
2x-2x+1+3=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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