2(x-3)+9=3(x+1)+8

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Solution for 2(x-3)+9=3(x+1)+8 equation: 



2(x-3)+9=3(x+1)+8

We move all terms to the left:

2(x-3)+9-(3(x+1)+8)=0

We multiply parentheses

2x-(3(x+1)+8)-6+9=0



We calculate terms in parentheses: -(3(x+1)+8), so:

3(x+1)+8

We multiply parentheses

3x+3+8

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

2x-(3x+11)+3=0

We get rid of parentheses

2x-3x-11+3=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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