2(x-3)+x=x+5-2(x-1)

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Solution for 2(x-3)+x=x+5-2(x-1) equation: 



2(x-3)+x=x+5-2(x-1)

We move all terms to the left:

2(x-3)+x-(x+5-2(x-1))=0

We add all the numbers together, and all the variables

x+2(x-3)-(x+5-2(x-1))=0

We multiply parentheses

x+2x-(x+5-2(x-1))-6=0



We calculate terms in parentheses: -(x+5-2(x-1)), so:

x+5-2(x-1)

determiningTheFunctionDomain
x-2(x-1)+5

We multiply parentheses

x-2x+2+5

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We add all the numbers together, and all the variables

3x-(-1x+7)-6=0

We get rid of parentheses

3x+1x-7-6=0

We add all the numbers together, and all the variables

4x-13=0

We move all terms containing x to the left, all other terms to the right

4x=13

x=13/4

x=3+1/4

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