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2(x-3)-2(x+1)=(x+1)
We move all terms to the left:
2(x-3)-2(x+1)-((x+1))=0
We multiply parentheses
2x-2x-((x+1))-6-2=0
We calculate terms in parentheses: -((x+1)), so:We add all the numbers together, and all the variables
(x+1)
We get rid of parentheses
x+1
Back to the equation:
-(x+1)
-(x+1)-8=0
We get rid of parentheses
-x-1-8=0
We add all the numbers together, and all the variables
-1x-9=0
We move all terms containing x to the left, all other terms to the right
-x=9
x=9/-1
x=-9
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