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2(x-3)-2=6x-4(1+x)
We move all terms to the left:
2(x-3)-2-(6x-4(1+x))=0
We add all the numbers together, and all the variables
2(x-3)-(6x-4(x+1))-2=0
We multiply parentheses
2x-(6x-4(x+1))-6-2=0
We calculate terms in parentheses: -(6x-4(x+1)), so:We add all the numbers together, and all the variables
6x-4(x+1)
We multiply parentheses
6x-4x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-(2x-4)-8=0
We get rid of parentheses
2x-2x+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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