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2(x-3)-3(1-2x)=3(2-x)-2(5-3x)
We move all terms to the left:
2(x-3)-3(1-2x)-(3(2-x)-2(5-3x))=0
We add all the numbers together, and all the variables
2(x-3)-3(-2x+1)-(3(-1x+2)-2(-3x+5))=0
We multiply parentheses
2x+6x-(3(-1x+2)-2(-3x+5))-6-3=0
We calculate terms in parentheses: -(3(-1x+2)-2(-3x+5)), so:We add all the numbers together, and all the variables
3(-1x+2)-2(-3x+5)
We multiply parentheses
-3x+6x+6-10
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
8x-(3x-4)-9=0
We get rid of parentheses
8x-3x+4-9=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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