2(x-3)-3(4-x)=4(2x-5)

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Solution for 2(x-3)-3(4-x)=4(2x-5) equation: 



2(x-3)-3(4-x)=4(2x-5)

We move all terms to the left:

2(x-3)-3(4-x)-(4(2x-5))=0

We add all the numbers together, and all the variables

2(x-3)-3(-1x+4)-(4(2x-5))=0

We multiply parentheses

2x+3x-(4(2x-5))-6-12=0



We calculate terms in parentheses: -(4(2x-5)), so:

4(2x-5)

We multiply parentheses

8x-20

Back to the equation:

-(8x-20)



We add all the numbers together, and all the variables

5x-(8x-20)-18=0

We get rid of parentheses

5x-8x+20-18=0

We add all the numbers together, and all the variables

-3x+2=0

We move all terms containing x to the left, all other terms to the right

-3x=-2

x=-2/-3

x=2/3

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