2(x-3)-3(x+2)=x+2-(x-3)

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Solution for 2(x-3)-3(x+2)=x+2-(x-3) equation: 



2(x-3)-3(x+2)=x+2-(x-3)

We move all terms to the left:

2(x-3)-3(x+2)-(x+2-(x-3))=0

We multiply parentheses

2x-3x-(x+2-(x-3))-6-6=0



We calculate terms in parentheses: -(x+2-(x-3)), so:

x+2-(x-3)

determiningTheFunctionDomain
x-(x-3)+2

We get rid of parentheses

x-x+3+2

We add all the numbers together, and all the variables

5

Back to the equation:

-(5)



We add all the numbers together, and all the variables

-1x-17=0

We move all terms containing x to the left, all other terms to the right

-x=17

x=17/-1

x=-17

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