2(x-3)-3(x+2)=x+2-(x-6)

Solution for 2(x-3)-3(x+2)=x+2-(x-6) equation:

2(x-3)-3(x+2)=x+2-(x-6)

We move all terms to the left:

2(x-3)-3(x+2)-(x+2-(x-6))=0

We multiply parentheses

2x-3x-(x+2-(x-6))-6-6=0


We calculate terms in parentheses: -(x+2-(x-6)), so:

x+2-(x-6)

determiningTheFunctionDomain
x-(x-6)+2

We get rid of parentheses

x-x+6+2

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)


We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20