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2(x-3)-3(x-2)=12
We move all terms to the left:
2(x-3)-3(x-2)-(12)=0
We multiply parentheses
2x-3x-6+6-12=0
We add all the numbers together, and all the variables
-1x-12=0
We move all terms containing x to the left, all other terms to the right
-x=12
x=12/-1
x=-12
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