2(x-3)-3(x-2)=x+2(x-6)

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Solution for 2(x-3)-3(x-2)=x+2(x-6) equation: 



2(x-3)-3(x-2)=x+2(x-6)

We move all terms to the left:

2(x-3)-3(x-2)-(x+2(x-6))=0

We multiply parentheses

2x-3x-(x+2(x-6))-6+6=0



We calculate terms in parentheses: -(x+2(x-6)), so:

x+2(x-6)

We multiply parentheses

x+2x-12

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

-1x-(3x-12)=0

We get rid of parentheses

-1x-3x+12=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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