2(x-3)-3(x-2)=x+5-(x-1)

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Solution for 2(x-3)-3(x-2)=x+5-(x-1) equation: 



2(x-3)-3(x-2)=x+5-(x-1)

We move all terms to the left:

2(x-3)-3(x-2)-(x+5-(x-1))=0

We multiply parentheses

2x-3x-(x+5-(x-1))-6+6=0



We calculate terms in parentheses: -(x+5-(x-1)), so:

x+5-(x-1)

determiningTheFunctionDomain
x-(x-1)+5

We get rid of parentheses

x-x+1+5

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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