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2(x-3)-3(x-2)=x-(x-5)
We move all terms to the left:
2(x-3)-3(x-2)-(x-(x-5))=0
We multiply parentheses
2x-3x-(x-(x-5))-6+6=0
We calculate terms in parentheses: -(x-(x-5)), so:We add all the numbers together, and all the variables
x-(x-5)
We get rid of parentheses
x-x+5
We add all the numbers together, and all the variables
5
Back to the equation:
-(5)
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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