2(x-3)-3(x-2)=x-(x-5)

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Solution for 2(x-3)-3(x-2)=x-(x-5) equation: 



2(x-3)-3(x-2)=x-(x-5)

We move all terms to the left:

2(x-3)-3(x-2)-(x-(x-5))=0

We multiply parentheses

2x-3x-(x-(x-5))-6+6=0



We calculate terms in parentheses: -(x-(x-5)), so:

x-(x-5)

We get rid of parentheses

x-x+5

We add all the numbers together, and all the variables

5

Back to the equation:

-(5)



We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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