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2(x-3)-3(x-3)=5(x-5)
We move all terms to the left:
2(x-3)-3(x-3)-(5(x-5))=0
We multiply parentheses
2x-3x-(5(x-5))-6+9=0
We calculate terms in parentheses: -(5(x-5)), so:We add all the numbers together, and all the variables
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
-1x-(5x-25)+3=0
We get rid of parentheses
-1x-5x+25+3=0
We add all the numbers together, and all the variables
-6x+28=0
We move all terms containing x to the left, all other terms to the right
-6x=-28
x=-28/-6
x=4+2/3
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