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2(x-3)-4(x+2)=2-3x
We move all terms to the left:
2(x-3)-4(x+2)-(2-3x)=0
We add all the numbers together, and all the variables
2(x-3)-4(x+2)-(-3x+2)=0
We multiply parentheses
2x-4x-(-3x+2)-6-8=0
We get rid of parentheses
2x-4x+3x-2-6-8=0
We add all the numbers together, and all the variables
x-16=0
We move all terms containing x to the left, all other terms to the right
x=16
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