2(x-3)-5(3x+1)-6=3(x-5)

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Solution for 2(x-3)-5(3x+1)-6=3(x-5) equation:



2(x-3)-5(3x+1)-6=3(x-5)
We move all terms to the left:
2(x-3)-5(3x+1)-6-(3(x-5))=0
We multiply parentheses
2x-15x-(3(x-5))-6-5-6=0
We calculate terms in parentheses: -(3(x-5)), so:
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
We add all the numbers together, and all the variables
-13x-(3x-15)-17=0
We get rid of parentheses
-13x-3x+15-17=0
We add all the numbers together, and all the variables
-16x-2=0
We move all terms containing x to the left, all other terms to the right
-16x=2
x=2/-16
x=-1/8

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