2(x-3)-5=-4(2x-3)+7

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Solution for 2(x-3)-5=-4(2x-3)+7 equation:



2(x-3)-5=-4(2x-3)+7
We move all terms to the left:
2(x-3)-5-(-4(2x-3)+7)=0
We multiply parentheses
2x-(-4(2x-3)+7)-6-5=0
We calculate terms in parentheses: -(-4(2x-3)+7), so:
-4(2x-3)+7
We multiply parentheses
-8x+12+7
We add all the numbers together, and all the variables
-8x+19
Back to the equation:
-(-8x+19)
We add all the numbers together, and all the variables
2x-(-8x+19)-11=0
We get rid of parentheses
2x+8x-19-11=0
We add all the numbers together, and all the variables
10x-30=0
We move all terms containing x to the left, all other terms to the right
10x=30
x=30/10
x=3

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