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2(x-3)-5=4x-2(1+x)
We move all terms to the left:
2(x-3)-5-(4x-2(1+x))=0
We add all the numbers together, and all the variables
2(x-3)-(4x-2(x+1))-5=0
We multiply parentheses
2x-(4x-2(x+1))-6-5=0
We calculate terms in parentheses: -(4x-2(x+1)), so:We add all the numbers together, and all the variables
4x-2(x+1)
We multiply parentheses
4x-2x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
2x-(2x-2)-11=0
We get rid of parentheses
2x-2x+2-11=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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