2(x-3)/3=(3x+1)/5+9

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Solution for 2(x-3)/3=(3x+1)/5+9 equation:



2(x-3)/3=(3x+1)/5+9
We move all terms to the left:
2(x-3)/3-((3x+1)/5+9)=0
We calculate fractions
(10x-30)/()+(-((3x+1)*3)/()=0
We calculate terms in parentheses: +(-((3x+1)*3)/(), so:
-((3x+1)*3)/(
We multiply all the terms by the denominator
-((3x+1)*3)
We calculate terms in parentheses: -((3x+1)*3), so:
(3x+1)*3
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
We get rid of parentheses
-9x-3
Back to the equation:
+(-9x-3)
We get rid of parentheses
(10x-30)/()-9x-3=0
We multiply all the terms by the denominator
(10x-30)-9x*()-3*()=0
We add all the numbers together, and all the variables
(10x-30)-9x*()=0
We get rid of parentheses
10x-9x*()-30=0
We move all terms containing x to the left, all other terms to the right
10x-9x*()=30

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