2(x-3)/3=(3x+1)/5+9

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Solution for 2(x-3)/3=(3x+1)/5+9 equation: 



2(x-3)/3=(3x+1)/5+9

We move all terms to the left:

2(x-3)/3-((3x+1)/5+9)=0

We calculate fractions


(10x-30)/()+(-((3x+1)*3)/()=0



We calculate terms in parentheses: +(-((3x+1)*3)/(), so:

-((3x+1)*3)/(

We multiply all the terms by the denominator


-((3x+1)*3)



We calculate terms in parentheses: -((3x+1)*3), so:

(3x+1)*3

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

-9x-3

Back to the equation:

+(-9x-3)



We get rid of parentheses

(10x-30)/()-9x-3=0

We multiply all the terms by the denominator


(10x-30)-9x*()-3*()=0

We add all the numbers together, and all the variables

(10x-30)-9x*()=0

We get rid of parentheses

10x-9x*()-30=0

We move all terms containing x to the left, all other terms to the right

10x-9x*()=30

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