2(x-3)/3=2(x+2)/8

Solution for 2(x-3)/3=2(x+2)/8 equation:

2(x-3)/3=2(x+2)/8

We move all terms to the left:

2(x-3)/3-(2(x+2)/8)=0

We calculate fractions


2x/()+(-(2(x+2)*3)/()=0


We calculate terms in parentheses: +(-(2(x+2)*3)/(), so:

-(2(x+2)*3)/(

We multiply all the terms by the denominator


-(2(x+2)*3)


We calculate terms in parentheses: -(2(x+2)*3), so:

2(x+2)*3

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)


We get rid of parentheses

-6x-12

Back to the equation:

+(-6x-12)


We get rid of parentheses

2x/()-6x-12=0

We multiply all the terms by the denominator


2x-6x*()-12*()=0

We add all the numbers together, and all the variables

2x-6x*()=0