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2(x-3)/3x+1=3/10
We move all terms to the left:
2(x-3)/3x+1-(3/10)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2(x-3)/3x+1-(+3/10)=0
We get rid of parentheses
2(x-3)/3x+1-3/10=0
We calculate fractions
(20x-60)/30x+(-9x)/30x+1=0
We multiply all the terms by the denominator
(20x-60)+(-9x)+1*30x=0
Wy multiply elements
(20x-60)+(-9x)+30x=0
We get rid of parentheses
20x-9x+30x-60=0
We add all the numbers together, and all the variables
41x-60=0
We move all terms containing x to the left, all other terms to the right
41x=60
x=60/41
x=1+19/41
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