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2(x-3)34(x+1)=5(x-1)+x+3
We move all terms to the left:
2(x-3)34(x+1)-(5(x-1)+x+3)=0
We calculate terms in parentheses: -(5(x-1)+x+3), so:We get rid of parentheses
5(x-1)+x+3
We add all the numbers together, and all the variables
x+5(x-1)+3
We multiply parentheses
x+5x-5+3
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
2(x-3)34(x+1)-6x+2=0
We add all the numbers together, and all the variables
-6x+2(x-3)34(x+1)+2=0
We move all terms containing x to the left, all other terms to the right
-6x+2(x-3)34(x+1)=-2
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