2(x-3)=(x+1)-8

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Solution for 2(x-3)=(x+1)-8 equation: 



2(x-3)=(x+1)-8

We move all terms to the left:

2(x-3)-((x+1)-8)=0

We multiply parentheses

2x-((x+1)-8)-6=0



We calculate terms in parentheses: -((x+1)-8), so:

(x+1)-8

We get rid of parentheses

x+1-8

We add all the numbers together, and all the variables

x-7

Back to the equation:

-(x-7)



We get rid of parentheses

2x-x+7-6=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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