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2(x-3)=(x+2)
We move all terms to the left:
2(x-3)-((x+2))=0
We multiply parentheses
2x-((x+2))-6=0
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
2x-x-2-6=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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