2(x-3)=(x+3)/3+2x

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Solution for 2(x-3)=(x+3)/3+2x equation: 



2(x-3)=(x+3)/3+2x

We move all terms to the left:

2(x-3)-((x+3)/3+2x)=0



Domain of the equation: 3+2x)!=0

We move all terms containing x to the left, all other terms to the right

2x)!=-3

x!=-3/1

x!=-3

x∈R



We multiply parentheses

2x-((x+3)/3+2x)-6=0

We multiply all the terms by the denominator


2x*3+2x)-((x+3)+2x)-6*3=0

Wy multiply elements

6x+2x)-((x+3)+2x)-6*3=0

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