2(x-3)=(x-10)+7

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Solution for 2(x-3)=(x-10)+7 equation: 



2(x-3)=(x-10)+7

We move all terms to the left:

2(x-3)-((x-10)+7)=0

We multiply parentheses

2x-((x-10)+7)-6=0



We calculate terms in parentheses: -((x-10)+7), so:

(x-10)+7

We get rid of parentheses

x-10+7

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

2x-x+3-6=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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