2(x-3)=(x-7)+7

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Solution for 2(x-3)=(x-7)+7 equation: 



2(x-3)=(x-7)+7

We move all terms to the left:

2(x-3)-((x-7)+7)=0

We multiply parentheses

2x-((x-7)+7)-6=0



We calculate terms in parentheses: -((x-7)+7), so:

(x-7)+7

We get rid of parentheses

x-7+7

We add all the numbers together, and all the variables

x

Back to the equation:

-(x)



We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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