2(x-3)=-3(-2x-4)+6

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Solution for 2(x-3)=-3(-2x-4)+6 equation: 



2(x-3)=-3(-2x-4)+6

We move all terms to the left:

2(x-3)-(-3(-2x-4)+6)=0

We multiply parentheses

2x-(-3(-2x-4)+6)-6=0



We calculate terms in parentheses: -(-3(-2x-4)+6), so:

-3(-2x-4)+6

We multiply parentheses

6x+12+6

We add all the numbers together, and all the variables

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

2x-6x-18-6=0

We add all the numbers together, and all the variables

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6

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