2(x-3)=-3(x-2)+8

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Solution for 2(x-3)=-3(x-2)+8 equation: 



2(x-3)=-3(x-2)+8

We move all terms to the left:

2(x-3)-(-3(x-2)+8)=0

We multiply parentheses

2x-(-3(x-2)+8)-6=0



We calculate terms in parentheses: -(-3(x-2)+8), so:

-3(x-2)+8

We multiply parentheses

-3x+6+8

We add all the numbers together, and all the variables

-3x+14

Back to the equation:

-(-3x+14)



We get rid of parentheses

2x+3x-14-6=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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