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2(x-3)=-3x+5(x+2)
We move all terms to the left:
2(x-3)-(-3x+5(x+2))=0
We multiply parentheses
2x-(-3x+5(x+2))-6=0
We calculate terms in parentheses: -(-3x+5(x+2)), so:We get rid of parentheses
-3x+5(x+2)
We multiply parentheses
-3x+5x+10
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
2x-2x-10-6=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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