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2(x-3)=11(x+2)
We move all terms to the left:
2(x-3)-(11(x+2))=0
We multiply parentheses
2x-(11(x+2))-6=0
We calculate terms in parentheses: -(11(x+2)), so:We get rid of parentheses
11(x+2)
We multiply parentheses
11x+22
Back to the equation:
-(11x+22)
2x-11x-22-6=0
We add all the numbers together, and all the variables
-9x-28=0
We move all terms containing x to the left, all other terms to the right
-9x=28
x=28/-9
x=-3+1/9
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