2(x-3)=11-5(3x+1)

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Solution for 2(x-3)=11-5(3x+1) equation: 



2(x-3)=11-5(3x+1)

We move all terms to the left:

2(x-3)-(11-5(3x+1))=0

We multiply parentheses

2x-(11-5(3x+1))-6=0



We calculate terms in parentheses: -(11-5(3x+1)), so:

11-5(3x+1)

determiningTheFunctionDomain
-5(3x+1)+11

We multiply parentheses

-15x-5+11

We add all the numbers together, and all the variables

-15x+6

Back to the equation:

-(-15x+6)



We get rid of parentheses

2x+15x-6-6=0

We add all the numbers together, and all the variables

17x-12=0

We move all terms containing x to the left, all other terms to the right

17x=12

x=12/17

x=12/17

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