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2(x-3)=2(x-4)
We move all terms to the left:
2(x-3)-(2(x-4))=0
We multiply parentheses
2x-(2(x-4))-6=0
We calculate terms in parentheses: -(2(x-4)), so:We get rid of parentheses
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
2x-2x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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