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2(x-3)=3(2x-5)
We move all terms to the left:
2(x-3)-(3(2x-5))=0
We multiply parentheses
2x-(3(2x-5))-6=0
We calculate terms in parentheses: -(3(2x-5)), so:We get rid of parentheses
3(2x-5)
We multiply parentheses
6x-15
Back to the equation:
-(6x-15)
2x-6x+15-6=0
We add all the numbers together, and all the variables
-4x+9=0
We move all terms containing x to the left, all other terms to the right
-4x=-9
x=-9/-4
x=2+1/4
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