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2(x-3)=3(x+1)+(9-x)
We move all terms to the left:
2(x-3)-(3(x+1)+(9-x))=0
We add all the numbers together, and all the variables
2(x-3)-(3(x+1)+(-1x+9))=0
We multiply parentheses
2x-(3(x+1)+(-1x+9))-6=0
We calculate terms in parentheses: -(3(x+1)+(-1x+9)), so:We get rid of parentheses
3(x+1)+(-1x+9)
We multiply parentheses
3x+(-1x+9)+3
We get rid of parentheses
3x-1x+9+3
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
2x-2x-12-6=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation
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