2(x-3)=3(x+1)+x

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Solution for 2(x-3)=3(x+1)+x equation: 



2(x-3)=3(x+1)+x

We move all terms to the left:

2(x-3)-(3(x+1)+x)=0

We multiply parentheses

2x-(3(x+1)+x)-6=0



We calculate terms in parentheses: -(3(x+1)+x), so:

3(x+1)+x

We add all the numbers together, and all the variables

x+3(x+1)

We multiply parentheses

x+3x+3

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We get rid of parentheses

2x-4x-3-6=0

We add all the numbers together, and all the variables

-2x-9=0

We move all terms containing x to the left, all other terms to the right

-2x=9

x=9/-2

x=-4+1/2

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