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2(x-3)=3(x+15)
We move all terms to the left:
2(x-3)-(3(x+15))=0
We multiply parentheses
2x-(3(x+15))-6=0
We calculate terms in parentheses: -(3(x+15)), so:We get rid of parentheses
3(x+15)
We multiply parentheses
3x+45
Back to the equation:
-(3x+45)
2x-3x-45-6=0
We add all the numbers together, and all the variables
-1x-51=0
We move all terms containing x to the left, all other terms to the right
-x=51
x=51/-1
x=-51
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