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2(x-3)=3(x+2)-x
We move all terms to the left:
2(x-3)-(3(x+2)-x)=0
We multiply parentheses
2x-(3(x+2)-x)-6=0
We calculate terms in parentheses: -(3(x+2)-x), so:We get rid of parentheses
3(x+2)-x
We add all the numbers together, and all the variables
-1x+3(x+2)
We multiply parentheses
-1x+3x+6
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
2x-2x-6-6=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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