2(x-3)=3/2(x-4)+x/2

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Solution for 2(x-3)=3/2(x-4)+x/2 equation: 


x in (-oo:+oo)

2*(x-3) = (3/2)*(x-4)+x/2 // - (3/2)*(x-4)+x/2

2*(x-3)-((3/2)*(x-4))-(x/2) = 0

2*(x-3)+(-3/2)*(x-4)-(x/2) = 0

2*(x-3)-3/2*(x-4)-x/2 = 0

(2^2*(x-3))/2+(-3/2*2*(x-4))/2-x/2 = 0

2^2*(x-3)-3/2*2*(x-4)-x = 0

x-x = 0

0 = 0

0/2 = 0

0/2 = 0 // * 2

0 = 0

x belongs to the empty set

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