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2(x-3)=4(1+x)
We move all terms to the left:
2(x-3)-(4(1+x))=0
We add all the numbers together, and all the variables
2(x-3)-(4(x+1))=0
We multiply parentheses
2x-(4(x+1))-6=0
We calculate terms in parentheses: -(4(x+1)), so:We get rid of parentheses
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
2x-4x-4-6=0
We add all the numbers together, and all the variables
-2x-10=0
We move all terms containing x to the left, all other terms to the right
-2x=10
x=10/-2
x=-5
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