2(x-3)=4(x+1)-2

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Solution for 2(x-3)=4(x+1)-2 equation: 



2(x-3)=4(x+1)-2

We move all terms to the left:

2(x-3)-(4(x+1)-2)=0

We multiply parentheses

2x-(4(x+1)-2)-6=0



We calculate terms in parentheses: -(4(x+1)-2), so:

4(x+1)-2

We multiply parentheses

4x+4-2

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

2x-4x-2-6=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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