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2(x-3)=4(x+4)-6x
We move all terms to the left:
2(x-3)-(4(x+4)-6x)=0
We multiply parentheses
2x-(4(x+4)-6x)-6=0
We calculate terms in parentheses: -(4(x+4)-6x), so:We get rid of parentheses
4(x+4)-6x
We add all the numbers together, and all the variables
-6x+4(x+4)
We multiply parentheses
-6x+4x+16
We add all the numbers together, and all the variables
-2x+16
Back to the equation:
-(-2x+16)
2x+2x-16-6=0
We add all the numbers together, and all the variables
4x-22=0
We move all terms containing x to the left, all other terms to the right
4x=22
x=22/4
x=5+1/2
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