2(x-3)=4+(x-2)

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Solution for 2(x-3)=4+(x-2) equation: 



2(x-3)=4+(x-2)

We move all terms to the left:

2(x-3)-(4+(x-2))=0

We multiply parentheses

2x-(4+(x-2))-6=0



We calculate terms in parentheses: -(4+(x-2)), so:

4+(x-2)

determiningTheFunctionDomain
(x-2)+4

We get rid of parentheses

x-2+4

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

2x-x-2-6=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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