2(x-3)=6x+1-2(-7x-1)

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Solution for 2(x-3)=6x+1-2(-7x-1) equation: 



2(x-3)=6x+1-2(-7x-1)

We move all terms to the left:

2(x-3)-(6x+1-2(-7x-1))=0

We multiply parentheses

2x-(6x+1-2(-7x-1))-6=0



We calculate terms in parentheses: -(6x+1-2(-7x-1)), so:

6x+1-2(-7x-1)

determiningTheFunctionDomain
6x-2(-7x-1)+1

We multiply parentheses

6x+14x+2+1

We add all the numbers together, and all the variables

20x+3

Back to the equation:

-(20x+3)



We get rid of parentheses

2x-20x-3-6=0

We add all the numbers together, and all the variables

-18x-9=0

We move all terms containing x to the left, all other terms to the right

-18x=9

x=9/-18

x=-1/2

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