2(x-3)=7x+10-x

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Solution for 2(x-3)=7x+10-x equation: 



2(x-3)=7x+10-x

We move all terms to the left:

2(x-3)-(7x+10-x)=0

We add all the numbers together, and all the variables

2(x-3)-(6x+10)=0

We multiply parentheses

2x-(6x+10)-6=0

We get rid of parentheses

2x-6x-10-6=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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