2(x-4)+1=3(x+1)-6

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Solution for 2(x-4)+1=3(x+1)-6 equation: 



2(x-4)+1=3(x+1)-6

We move all terms to the left:

2(x-4)+1-(3(x+1)-6)=0

We multiply parentheses

2x-(3(x+1)-6)-8+1=0



We calculate terms in parentheses: -(3(x+1)-6), so:

3(x+1)-6

We multiply parentheses

3x+3-6

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

2x-(3x-3)-7=0

We get rid of parentheses

2x-3x+3-7=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4

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