2(x-4)+1=7-(2x+3)

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Solution for 2(x-4)+1=7-(2x+3) equation:



2(x-4)+1=7-(2x+3)
We move all terms to the left:
2(x-4)+1-(7-(2x+3))=0
We multiply parentheses
2x-(7-(2x+3))-8+1=0
We calculate terms in parentheses: -(7-(2x+3)), so:
7-(2x+3)
determiningTheFunctionDomain -(2x+3)+7
We get rid of parentheses
-2x-3+7
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
We add all the numbers together, and all the variables
2x-(-2x+4)-7=0
We get rid of parentheses
2x+2x-4-7=0
We add all the numbers together, and all the variables
4x-11=0
We move all terms containing x to the left, all other terms to the right
4x=11
x=11/4
x=2+3/4

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