2(x-4)+2x=4(x+5)-28

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Solution for 2(x-4)+2x=4(x+5)-28 equation: 


Simplifying
2(x + -4) + 2x = 4(x + 5) + -28

Reorder the terms:
2(-4 + x) + 2x = 4(x + 5) + -28
(-4 * 2 + x * 2) + 2x = 4(x + 5) + -28
(-8 + 2x) + 2x = 4(x + 5) + -28

Combine like terms: 2x + 2x = 4x
-8 + 4x = 4(x + 5) + -28

Reorder the terms:
-8 + 4x = 4(5 + x) + -28
-8 + 4x = (5 * 4 + x * 4) + -28
-8 + 4x = (20 + 4x) + -28

Reorder the terms:
-8 + 4x = 20 + -28 + 4x

Combine like terms: 20 + -28 = -8
-8 + 4x = -8 + 4x

Add '8' to each side of the equation.
-8 + 8 + 4x = -8 + 8 + 4x

Combine like terms: -8 + 8 = 0
0 + 4x = -8 + 8 + 4x
4x = -8 + 8 + 4x

Combine like terms: -8 + 8 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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