2(x-4)+2x=x+4(x-2)

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Solution for 2(x-4)+2x=x+4(x-2) equation:



2(x-4)+2x=x+4(x-2)
We move all terms to the left:
2(x-4)+2x-(x+4(x-2))=0
We add all the numbers together, and all the variables
2x+2(x-4)-(x+4(x-2))=0
We multiply parentheses
2x+2x-(x+4(x-2))-8=0
We calculate terms in parentheses: -(x+4(x-2)), so:
x+4(x-2)
We multiply parentheses
x+4x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
We add all the numbers together, and all the variables
4x-(5x-8)-8=0
We get rid of parentheses
4x-5x+8-8=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0

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