2(x-4)+3(2x-6)=8x-10

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Solution for 2(x-4)+3(2x-6)=8x-10 equation: 


Simplifying
2(x + -4) + 3(2x + -6) = 8x + -10

Reorder the terms:
2(-4 + x) + 3(2x + -6) = 8x + -10
(-4 * 2 + x * 2) + 3(2x + -6) = 8x + -10
(-8 + 2x) + 3(2x + -6) = 8x + -10

Reorder the terms:
-8 + 2x + 3(-6 + 2x) = 8x + -10
-8 + 2x + (-6 * 3 + 2x * 3) = 8x + -10
-8 + 2x + (-18 + 6x) = 8x + -10

Reorder the terms:
-8 + -18 + 2x + 6x = 8x + -10

Combine like terms: -8 + -18 = -26
-26 + 2x + 6x = 8x + -10

Combine like terms: 2x + 6x = 8x
-26 + 8x = 8x + -10

Reorder the terms:
-26 + 8x = -10 + 8x

Add '-8x' to each side of the equation.
-26 + 8x + -8x = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
-26 + 0 = -10 + 8x + -8x
-26 = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
-26 = -10 + 0
-26 = -10

Solving
-26 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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